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Let through Energy - Cable Sizing

Why let through energy of cable is calculated and compared against protective device let through energy, when adiabatic equation and disconnection time check is used to verify the cable sizes? or this let thru energy verification is applied only for current limiting breakers / fuses?
  • AJJewsbury:
    To be clear, I wanted to ask, When the cables have been already verified using adiabatic equation, Do I still need to check the cables for let through energy verification?

    In principle they're both the same thing (S = √(I2t)/k is the same a S2k2 = I2t, just re-arranged (divide through by k and square both sides)) - but in practice people often refer to different conditions - e.g. the adiabatic is often only considered when sizing c.p.c.s - i.e. for Earth Faults whereas L-N, L-L and L-L-L faults are more commonly thought of when thinking of energy let-though.  Of course faults between live conductors can produce quite different levels fault currents than L-PE faults - so a calculation based on an earth fault current might not be valid for the other kinds of faults.


    As a first approximation if a conductor is "reduced" - i.e. it has a rating below that of its protective device (Iz < In) - then some check will likely be necessary.


    Also keep in mind that the worst case isn't necessarily a fault at the far end of the circuit - that gives the lowest fault current and likely the longest disconnection time - and for fuses probably the highest energy let-through but for MCBs faults with higher currents (e.g. a fault next to the MCB) often don't disconnect significantly faster than a far-off fault - so I²t can often be higher. Unfortunatley some text book examples seem to have been written with fuses in mind and miss that point.


        - Andy.


    Though both the equations are same (just rearrangement) but the I2t value comes from the manufacturer in case of verifying the let through energy. Now my question is can we use this let through energy value (received from the manufacturer in the form of curve) to apply in this adiabatic equation S=(I√t)/k, to find out the minimum required CSA of conductor


  • Though both the equations are same (just rearrangement) but the I2t value comes from the manufacturer in case of verifying the let through energy. Now my question is can we use this let through energy value (received from the manufacturer in the form of curve) to apply in this adiabatic equation

    In principle you can use the manufacturer's I²t instead of the fault current I and the disconnection time t -  but in general t is only available for disconnections times over 0.1s (certainly in BS 7671) - and often I²t values are only applicable for 'instantaneous' disconnection (i.e. <0.1s) - so often the choice is made for you.


      - Andy.
  • Nick Parker:
     


    Though both the equations are same (just rearrangement) but the I2t value comes from the manufacturer in case of verifying the let through energy. Now my question is can we use this let through energy value (received from the manufacturer in the form of curve) to apply in this adiabatic equation S=(I√t)/k, to find out the minimum required CSA of conductor




    That's the point, the expression you stated does not include the term (I2t), which is the value quoted by the mcb/RCBO manufacturer, or from BS EN 60898 or BS EN 61009.


    The minimum S in the case you stated would have to be given by:


    S={√(I2t)}/k


    The different ways in which the adaibatic formula or adiabatic criterion is presented in BS 7671 is not helpful.


    For example, have a look at the following Regulations:

     



    • 434.5.2 (for current carrying conductors) uses both of the following (depending on device type) but does not print the first one as an equation-type expression, it's in the words of the 2nd para of the Reg
      • k2S2≥I2t

    • t=(k2S2)/I2


    • 543.1.3 (for protective conductors) uses only S={√(I2t)}/k