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INTEGRATION (RE)

Former Community Member
Former Community Member

 

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  • Former Community Member
    0 Former Community Member

    Hi Leslie,

    Normally I would be the last to try to pit a programmable calculator against the might of Mathcad!!

    However it is very simple to use a programmable calculator that is pre-programmed with Simpson's rule (such as Sharp model EL-5120). Evaluating the function integral ( [ln x]^2.3 . dx ) between the limits 10^5 and 1 on the EL-5120, with its default of 100 increments, and with Mathcad PLUS 6.0 gave the same result ( 2.268 * 10^7 ) to three decimal places. The EL-5120 took 45 seconds versus the instantaneous result with Mathcad.

    The number of increments can be specified by the user on the EL-5120.

    The EL-5120 gives an error code if the lower limit of the definite integral of the above-mentioned function is set below 1, the reason being it cannot handle the resulting complex number. This does not seem to me to be a problem in the evaluation of a function that I would expect to be integrated with a lower limit equal to or greater than 1.

    Regards,
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  • Former Community Member
    0 Former Community Member

    Hi Leslie,

    Normally I would be the last to try to pit a programmable calculator against the might of Mathcad!!

    However it is very simple to use a programmable calculator that is pre-programmed with Simpson's rule (such as Sharp model EL-5120). Evaluating the function integral ( [ln x]^2.3 . dx ) between the limits 10^5 and 1 on the EL-5120, with its default of 100 increments, and with Mathcad PLUS 6.0 gave the same result ( 2.268 * 10^7 ) to three decimal places. The EL-5120 took 45 seconds versus the instantaneous result with Mathcad.

    The number of increments can be specified by the user on the EL-5120.

    The EL-5120 gives an error code if the lower limit of the definite integral of the above-mentioned function is set below 1, the reason being it cannot handle the resulting complex number. This does not seem to me to be a problem in the evaluation of a function that I would expect to be integrated with a lower limit equal to or greater than 1.

    Regards,
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