Hi I would like to ask the community if we can set up a post for a new energy system I have been working on ,I think it works out more efficient and ecologically better , and its large scale thinking for energy systems , and now I need to check through my figures and need the views of IET thinkers for instance on combustion , post combustion chemistry , it unfolds into quite a complex system which I have been working on for 8 years , but enables us to get more energy from wastes and perhaps helps to move to biomaterials. I have an interest as environmental thinker and have designed the system to go through to government funding phases and pretty confident it works well in a number of questions around energy and environmental thinking .
Opps stoich figure for Hydrogen combustion is 0.5 m3 of O2 per m3 of Hydrogen , my apologies
1 kw equals 3600kj/hr so 1mw equals 3,600,000 kj/hr
So 500MW equals 1,800,000,000 kj/hr (that is if you could convert at 100% efficiency)
The latest GE/Siemens H class gas turbines claim to convert 64% of fuel value Kj into Kw (but lets call it 60% to help visualise things) so at 60% efficiency our gas turbine is consuming 1,800,000,000 kj x0.4 === 2,520,000,000 kj , as methane is around 39000kj a m3 so something like 65,000 m3 of Ch4 is consumed for a 500MW turbine (and around 65000 m3 of CO2 every hour is made and a kj per Mw fig of 5,040,000KJ), This beats our coal fired plant at 500Mw it would be emitting around 350,000kg /hr of CO2 or 190,000m3/hr , in fact in Co2 terms per MW its more than twice as good as air drafted electricity generation plants.
But this might not be the whole story if I stick with Methane and a 500Mw power plant can I beat the gas turbine ?? well a gas steam boiler could be more efficient ,than a boiler that has to burn a solid fuel so a 90% boiler should be possible, our J W Turk plant requires 12,250,000 KJ per Mw , so 500Mw should be around 6,125,000,000 kj , however a 10% more efficient boiler means 10% less fuel or 5,512,500,000 kj so around 141,000 m3 /hr as an air drafted system.
But what if we use an oxy fuel system ?? , no nitrogen to heat up , complete combustion ( I would need to do some complex gaseous heating equations at this point but lets call the removal of N2 to be worth a 14% reduction in fuel. so 121,550 m3 of Ch4 , the gas turbine is still twice as efficient at this point in fuel use terms , and a stack loss of 10% (4,740,450,000,kj === 4,740,450 000 x .0.1 =474,045,000kj ) if we could recover this exhaust heat and put it back into the combustion ,then only 4,266,405,000 kj would be required or 109,395m3 of CH4
Opps stoich figure for Hydrogen combustion is 0.5 m3 of O2 per m3 of Hydrogen , my apologies
1 kw equals 3600kj/hr so 1mw equals 3,600,000 kj/hr
So 500MW equals 1,800,000,000 kj/hr (that is if you could convert at 100% efficiency)
The latest GE/Siemens H class gas turbines claim to convert 64% of fuel value Kj into Kw (but lets call it 60% to help visualise things) so at 60% efficiency our gas turbine is consuming 1,800,000,000 kj x0.4 === 2,520,000,000 kj , as methane is around 39000kj a m3 so something like 65,000 m3 of Ch4 is consumed for a 500MW turbine (and around 65000 m3 of CO2 every hour is made and a kj per Mw fig of 5,040,000KJ), This beats our coal fired plant at 500Mw it would be emitting around 350,000kg /hr of CO2 or 190,000m3/hr , in fact in Co2 terms per MW its more than twice as good as air drafted electricity generation plants.
But this might not be the whole story if I stick with Methane and a 500Mw power plant can I beat the gas turbine ?? well a gas steam boiler could be more efficient ,than a boiler that has to burn a solid fuel so a 90% boiler should be possible, our J W Turk plant requires 12,250,000 KJ per Mw , so 500Mw should be around 6,125,000,000 kj , however a 10% more efficient boiler means 10% less fuel or 5,512,500,000 kj so around 141,000 m3 /hr as an air drafted system.
But what if we use an oxy fuel system ?? , no nitrogen to heat up , complete combustion ( I would need to do some complex gaseous heating equations at this point but lets call the removal of N2 to be worth a 14% reduction in fuel. so 121,550 m3 of Ch4 , the gas turbine is still twice as efficient at this point in fuel use terms , and a stack loss of 10% (4,740,450,000,kj === 4,740,450 000 x .0.1 =474,045,000kj ) if we could recover this exhaust heat and put it back into the combustion ,then only 4,266,405,000 kj would be required or 109,395m3 of CH4
