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Question on thermodynamics

Former Community Member
Former Community Member
Hello everyone, I have a question on the energy cost of compressing gas.

I didn't find a community about thermodynamics, so I post the question here..


When gas absorbs heat. its volume increases from v1 to v2. When we compress the volume of the same gas from v2 to v1, does the energy required equal to the heat it absorbs? Does the temperature affect the energy required?


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  • Former Community Member
    0 Former Community Member in reply to Chris Pearson

    Ian Evans:

    Firstly, your temperature adjustment for the resistance is incorrect: R(90°C) = R(20°C) × [1 + coeff × (90 - 20)]

    Secondly, are you considering an a.c. or d.c. system; if a.c. then you need to take account of the skin and proximity effects which will further increase the conductor resistance.

    Once you have the correct resistance you can calculate the losses from the conductor (joule losses).  All this energy needs to be removed from the conductor to maintain the temperature and you need to take account of all the heat transfer.  Your system would need to monitor the temperature because as soon as it gets above the required temperature the losses will increase and you will get thermal runaway.  As your system is 1 km long it is likely that the cooling gas will not be a constant temperature over the full length, it will be flowing around a system where the input will be colder than the output.  When considering cooling of a long conductor it is generally easier to think in terms of W/m (You are basically looking at a fluid dynamics problem to remove the W/m).

    Other things to consider are costs resulting from probable reduced reliability and additional maintenance - it isn't just about the savings in terms of energy losses.

     




    Thanks for pointing out the error.. I was misled by the Chinese article where the coeff is defined to "the change rate of resitivity per degree".

    I think the data in latter article is a little more exact.

    Actually, the benefit is not only the finacial saving. It also saves the non-renewable resources and the working efforts of workers in the mining or gas station..


    Well, the purpose I posted those equations is to make it more attractive instead of publishing a paper.. all the data are copied from the internet and their accuracy are not guaranteed.

    I'd like to find out if there's anybody who is interested in this topic and is willing to turn it into reality.. First of all, it should be feasible and valuable enough.

    Now it seems the biggest problem is to find out a suitable coolant. Any input is welcome~

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