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Reducing the fuel consumption of ships

Georgeb

We could greatly reduce the fuel consumption and emissions of ships if we used the energy of waves. This could done by adding a pipe all the way around the ship above sea level. Water enters the pipe at the bow and exits at the stern to push the ship forward. The pipe is higher and wider at the bow than the stern. Waves force water into one way openings at the bow to give pressurised water with potential energy. This pressurised water forces jets of water out at the stern.

All the pipework is above sea level so ships could be retroftted without the need to go into dry docks. There is no change to the laminar flow of water below sea level.

The motion of the ship adds to the kinetic energy of waves. By diverting this energy around the ship we can reduce drag and fuel consumption. This would be a low cost way to reduce greenhouse gas emissions without the need for people to reduce their standards of living.

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    Hi,

    Shipping companies calculate CO 2 emissions based on the simple formula "fuel consumption times emission factor". So the task is to measure the amount of fuel consumed. However, it is not as simple as it seems at first glance. A ship carries various types of fuel used in main engines, auxiliary engines, gas turbines, boilers or inert gas generators. Consumption scenarios range from the exclusive access of one consumer to one type to the simultaneous access of several consumers to one type. The fuels are fed to the consumers through ring lines, i.e. fuel that is not used strangely back to the tank or tank. In addition, some of the types have to be pumped between different containers to balance the ship. Complexity of the fuel system

    Based on Regulation 2015/757, since 2019 shipping companies have been required to submit a report on CO 2 emissions and other relevant information to the relevant Commission and flag authorities until 30 April each year for each ship under their responsibility. This report is transmitted through automated systems and exchange formats data.

    Most ships consume significantly less fuel per tonne of fuel compared to trucks or trains. However, the values ​​can vary greatly depending on the size of the ship or truck. Example: Container ships (3,000-8,000 TEU) emit about 17 grams of CO 2 per tonne-kilometer (tkm), while a truck (truck / truck 24-40 tons, average goods) emits around 68 grams / km / h.

    Vehicle fuel consumption per hour, depending on speed, Calculate and leaves with the following function: And (x) = 1, 4 + 0, 0025 X3 where: X .. Speed ​​in SM / h (nautical miles per hour) f (x) .. Diesel consumption in tons Which speed x should the captain choose if he wants to use the amount of fuel for at least 800 nm (nautical miles)? I can not move forward .. my thoughts: The faster the ship travels, the more it takes per hour, but it takes fewer hours to 800 nautical miles, so there are two interrelated functions.

    Vehicle fuel consumption per hour, depending on speed, Calculate and leaves with the following function: And (x) = 1, 4 + 0, 0025 X3 where: X .. Speed ​​in SM / h (nautical miles per hour) f (x) .. Diesel consumption in tons Which speed x should the captain choose if he wants to use the amount of fuel for at least 800 nm (nautical miles)? I can not move forward .. my thoughts: The faster the ship travels, the more it takes per hour, but it takes fewer hours to 800 nautical miles, so there are two interrelated functions. 1. Solve the formula v = s / t for t .. t = 800 / v ... so in our case 800 / x 2. Full consumption = t * Hourly consumption so G (t) = t * f (x) 3. It becomes G (x), which is then tested to a minimum, I reach x min = 6.542 sm / h, then the total consumption is the lowest with 256.8 t
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  • 0
    Hi,

    Shipping companies calculate CO 2 emissions based on the simple formula "fuel consumption times emission factor". So the task is to measure the amount of fuel consumed. However, it is not as simple as it seems at first glance. A ship carries various types of fuel used in main engines, auxiliary engines, gas turbines, boilers or inert gas generators. Consumption scenarios range from the exclusive access of one consumer to one type to the simultaneous access of several consumers to one type. The fuels are fed to the consumers through ring lines, i.e. fuel that is not used strangely back to the tank or tank. In addition, some of the types have to be pumped between different containers to balance the ship. Complexity of the fuel system

    Based on Regulation 2015/757, since 2019 shipping companies have been required to submit a report on CO 2 emissions and other relevant information to the relevant Commission and flag authorities until 30 April each year for each ship under their responsibility. This report is transmitted through automated systems and exchange formats data.

    Most ships consume significantly less fuel per tonne of fuel compared to trucks or trains. However, the values ​​can vary greatly depending on the size of the ship or truck. Example: Container ships (3,000-8,000 TEU) emit about 17 grams of CO 2 per tonne-kilometer (tkm), while a truck (truck / truck 24-40 tons, average goods) emits around 68 grams / km / h.

    Vehicle fuel consumption per hour, depending on speed, Calculate and leaves with the following function: And (x) = 1, 4 + 0, 0025 X3 where: X .. Speed ​​in SM / h (nautical miles per hour) f (x) .. Diesel consumption in tons Which speed x should the captain choose if he wants to use the amount of fuel for at least 800 nm (nautical miles)? I can not move forward .. my thoughts: The faster the ship travels, the more it takes per hour, but it takes fewer hours to 800 nautical miles, so there are two interrelated functions.

    Vehicle fuel consumption per hour, depending on speed, Calculate and leaves with the following function: And (x) = 1, 4 + 0, 0025 X3 where: X .. Speed ​​in SM / h (nautical miles per hour) f (x) .. Diesel consumption in tons Which speed x should the captain choose if he wants to use the amount of fuel for at least 800 nm (nautical miles)? I can not move forward .. my thoughts: The faster the ship travels, the more it takes per hour, but it takes fewer hours to 800 nautical miles, so there are two interrelated functions. 1. Solve the formula v = s / t for t .. t = 800 / v ... so in our case 800 / x 2. Full consumption = t * Hourly consumption so G (t) = t * f (x) 3. It becomes G (x), which is then tested to a minimum, I reach x min = 6.542 sm / h, then the total consumption is the lowest with 256.8 t
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