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K2s2 - Adiabatic for parallel cables

While verifying the cable selection for let through energy withstand, How should it be calculated for parallel cables? for example, 120sqmm of 2 runs (XLPE, copper), the K2s2 value is 294465600 (143 x 143 x 120 x 120) - Should I account for the 2 run by multiplying 2 to this value?
Parents

  • then multiplying the withstand of one conductor by two would make sense.



    On second thoughts perhaps that should be the withstand calculated for 2x the c.s.a. (k²(Sx2)²) rather than 2x the withstand (2x k²S²).


       - Andy.
Reply

  • then multiplying the withstand of one conductor by two would make sense.



    On second thoughts perhaps that should be the withstand calculated for 2x the c.s.a. (k²(Sx2)²) rather than 2x the withstand (2x k²S²).


       - Andy.
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