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The maximum permissible disconnection time is 0.4 s in TN system. Why and from where this value (0.4 s) is obtained?

Former Community Member
Former Community Member
The maximum permissible disconnection time in in the event of a short circuit between a phase conductor and a body or protective conductor or a protective-neutral conductor is 0.4 s in TN system. Does anybody know this value (0.4 s) obtains from where? How this value is obtained?
Parents
  • Andy,

    Protective bonding is accounted for in the calculation for touch voltage. I agree that there are variables and perhaps some arbitrary assumptions. The touch voltage used in the calculation is taken from;

    Ut = mxcxU /m+1

    Where Ut is the prospective touch voltage, m is the ratio of protective conductor resistance to phase conductor resistance m=R2/R1, c is similarly the relationship between the internal impedance and overall impedance c= R1+R2/Zs (taken as an arbitrary 0.8), U is 1.1 x Uo


    I should say, by the way, all this is taken from the Commentary on the 16th Edition by the excellent Mr Paul Cook.
Reply
  • Andy,

    Protective bonding is accounted for in the calculation for touch voltage. I agree that there are variables and perhaps some arbitrary assumptions. The touch voltage used in the calculation is taken from;

    Ut = mxcxU /m+1

    Where Ut is the prospective touch voltage, m is the ratio of protective conductor resistance to phase conductor resistance m=R2/R1, c is similarly the relationship between the internal impedance and overall impedance c= R1+R2/Zs (taken as an arbitrary 0.8), U is 1.1 x Uo


    I should say, by the way, all this is taken from the Commentary on the 16th Edition by the excellent Mr Paul Cook.
Children
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