A friend of mine brought a little device he made its a bridge rectifier fed straight off the mains then fed into a 900 uF capacitor the purpose of this little device is to try to make a CFL stay on for 10 seconds I don't know why it's his project. We tried this device out and after a few switch ons it popped a 5 amp fuse in the feed to my test bench so the question is what would be the charge current for a 900 uF capacitor? It made the ammeter in the feed to the test board kick up. So is there a way to work it out?
I would be happier with an L.E.D. emergency light. The energy stored in the battery will light the output for many hours. The automatic trickle charger will protect the battery from harm, and the whole emergency light will hopefully have been designed and made to safe standards. They can cost less than 20 quid each new. (Try C.P.C.). Mains on = battery charging. Mains off=light on. Even the little L.E.D. charging light conforming mains present can be quite bright in a dark room, even with the main L.E.D.s not working.
I would be happier with an L.E.D. emergency light. The energy stored in the battery will light the output for many hours. The automatic trickle charger will protect the battery from harm, and the whole emergency light will hopefully have been designed and made to safe standards. They can cost less than 20 quid each new. (Try C.P.C.). Mains on = battery charging. Mains off=light on. Even the little L.E.D. charging light conforming mains present can be quite bright in a dark room, even with the main L.E.D.s not working.
