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Type A rcd . EICR coding ? etc

aligarjon
Hi Guys.   Not been on for a long time, just had a bit of a search and couldn't really find anything so thought i would ask and see what you all thought.


1.  Are we or will we be coding type AC rcd's if there are LED's or induction hobs, lots of electronics  etc  present.

2. How much DC leakage does it actually take to saturate an rcd and cause  problem?

3. How much does a standard LED lamp or induction hob  leak ?

If we test an AC RCD with no load and it's fine then re-test it with all LED lights, induction hobs etc turned on and it operates correctly could we then say that it is ok with a note on EICR  OR EIC if installing any of the above.  


Obviously also on an EICR if the RCD then doesn't operate with it all on it becomes a C2 ?


Any thoughts



Gary
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  • 0
    So what happens when e.g. a motor's controller fires up? I have a mental image of current in the line conductor going through a rectifier and then stopping in a capacitor until it is charged up.

    But wouldn't you normally get an equal current flowing from the capacitor's -ve plate back to N? The Charge stays in the capacitor, rather than the current. In my head a capacitor is like an expansion vessel - a box with a flexible membrane in it and holes at opposite sides - pushing water in one side would push the same volume of water out of the other - but drop the pressure and the elasticity of the membrane and the water originally pushed in now flows back out - drawing back in an equal amount of water from the outlet side.


    Or if you prefer - like charging a battery - you still need both +ve and -ve connections to charge it - just like you need both to discharge it.


       - Andy.
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  • 0
    So what happens when e.g. a motor's controller fires up? I have a mental image of current in the line conductor going through a rectifier and then stopping in a capacitor until it is charged up.

    But wouldn't you normally get an equal current flowing from the capacitor's -ve plate back to N? The Charge stays in the capacitor, rather than the current. In my head a capacitor is like an expansion vessel - a box with a flexible membrane in it and holes at opposite sides - pushing water in one side would push the same volume of water out of the other - but drop the pressure and the elasticity of the membrane and the water originally pushed in now flows back out - drawing back in an equal amount of water from the outlet side.


    Or if you prefer - like charging a battery - you still need both +ve and -ve connections to charge it - just like you need both to discharge it.


       - Andy.
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