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CCC adjustments for short distances in long runs

Is there any guidance on how derating factors should be applied if for example a 40m run of cable was surface clipped in 'free air' for all but 150mm of it's length, where it passed through insulation?  Arguably the bit of the cable that would melt if overloaded would be the bit at the insulation as that is the 'worst case', and he 'safe' option would be to use the derating factor for cable installed in insulation, but arguably the ability of the cable to dissipate heat when fully enclosed in in insulation throughout it's length is very much different to a cable passing through a short distance of insulation, where the conductors would also conduct away heat from that location with some effectiveness.


What about a similar scenario with a cable running 38m on a tray in an open ceiling void, and the last 2m in a trunking to a distribution board with perhaps only a 25% fill?


Should you always calculate for the worst case, regardless off the length involved?  Is there any published guidance on this?


Jason.
Parents
  • The heat does indeed soak along the cable for a bit, so that the hot part benefits from the cooling further along, but it is only a matter of maybe a few tens of cable diameters, so probably only  a few inches rather than several feet.  A quick dive to come up through 100mm of loft insulation is probably OK,  running any distance in it, unwise, and if you really cannot re-route or improve the cooling then a step up in cable size for the tight section may be in order.


    A related thing, allows you  to estimate  the conductor temperature for a less than fully loaded circuit, realise the temperature rise goes as the power, so square of current.


    td = ta + ((Ib./Ita)2, x (tp - tr))


    Where


    td = temperature of cable at actual design current

    ta = ambient temp

    Ib = design current (average)

    Ita = tabulated current carrying capacity at ambient tr & max cable temp tp

    tp = permitted temperature

    tr = reference temperature.


    E.g.  for a 27 amp cable (say clipped direct T/E 2.5mm) carrying only 13A in an ambient of 25C

    (permitted temp is 70C and Reference temp is 30C.)


    td = 25 + (13/27)2,x(70-30) = 35C.

Reply
  • The heat does indeed soak along the cable for a bit, so that the hot part benefits from the cooling further along, but it is only a matter of maybe a few tens of cable diameters, so probably only  a few inches rather than several feet.  A quick dive to come up through 100mm of loft insulation is probably OK,  running any distance in it, unwise, and if you really cannot re-route or improve the cooling then a step up in cable size for the tight section may be in order.


    A related thing, allows you  to estimate  the conductor temperature for a less than fully loaded circuit, realise the temperature rise goes as the power, so square of current.


    td = ta + ((Ib./Ita)2, x (tp - tr))


    Where


    td = temperature of cable at actual design current

    ta = ambient temp

    Ib = design current (average)

    Ita = tabulated current carrying capacity at ambient tr & max cable temp tp

    tp = permitted temperature

    tr = reference temperature.


    E.g.  for a 27 amp cable (say clipped direct T/E 2.5mm) carrying only 13A in an ambient of 25C

    (permitted temp is 70C and Reference temp is 30C.)


    td = 25 + (13/27)2,x(70-30) = 35C.

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