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Appendix 4, section 6.1 equation 6

Former Community Member over 3 years ago

Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)

I get a correction factor of 0.95 for a 2A load.

Do i divide the mV/A/m by this factor ?

The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)

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0 Zoomup over 3 years ago

Andrew James Skinner:

Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)
I get a correction factor of 0.95 for a 2A load.
Do i divide the mV/A/m by this factor ?
The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)
I'd just round up the 0.952619 to 1.0 and call it a day. We ain't that precise in the real world of chucking in cables and “power” electrics.

Please read the last paragraph on page 381.

Also, please read the NOTE in 6.1 regarding the APPROXIMATE resistance temperature coefficient. The calculation is very approximate.

Z.
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0 Zoomup over 3 years ago

Andrew James Skinner:

Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)
I get a correction factor of 0.95 for a 2A load.
Do i divide the mV/A/m by this factor ?
The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)
I'd just round up the 0.952619 to 1.0 and call it a day. We ain't that precise in the real world of chucking in cables and “power” electrics.

Please read the last paragraph on page 381.

Also, please read the NOTE in 6.1 regarding the APPROXIMATE resistance temperature coefficient. The calculation is very approximate.

Z.
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