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Appendix 4, section 6.1 equation 6

Former Community Member over 3 years ago

Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)

I get a correction factor of 0.95 for a 2A load.

Do i divide the mV/A/m by this factor ?

The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)

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0 Sparkingchip over 3 years ago

Zoomup:

Sparkingchip:

Cable and drum around 100 kg.
That's only the weight of a big bloke.

Z.
And if that bloke went down on the floor it would probably take an ambulance crew of two with an inflatable cushion to get him back up again, I would not be able to lift him as a deadweight.
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0 Sparkingchip over 3 years ago

Zoomup:

Sparkingchip:

Cable and drum around 100 kg.
That's only the weight of a big bloke.

Z.
And if that bloke went down on the floor it would probably take an ambulance crew of two with an inflatable cushion to get him back up again, I would not be able to lift him as a deadweight.
Cancel
Vote Up 0 Vote Down

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