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Appendix 4, section 6.1 equation 6

Former Community Member
Former Community Member

 

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Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)

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I get a correction factor of 0.95 for a 2A load. 

Do i divide the mV/A/m by this factor ? 

The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)

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  • Zoomup: 
     

    Sparkingchip: 
     

    Cable and drum around 100 kg.

    That's only the weight of a big bloke.

     

    Z.

    And if that bloke went down on the floor it would  probably take an ambulance crew of two with an inflatable cushion to get him back up again, I would not be able to lift him as a deadweight. 

Reply
  • Zoomup: 
     

    Sparkingchip: 
     

    Cable and drum around 100 kg.

    That's only the weight of a big bloke.

     

    Z.

    And if that bloke went down on the floor it would  probably take an ambulance crew of two with an inflatable cushion to get him back up again, I would not be able to lift him as a deadweight. 

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