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Appendix 4, section 6.1 equation 6

Former Community Member
Former Community Member

 

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Hi I am working through equation 6 for an ambient temperature of 50 degrees for 1mm 90degC thermoplastic cable (Table 4E2A)

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I get a correction factor of 0.95 for a 2A load. 

Do i divide the mV/A/m by this factor ? 

The text says multiply, but that would mean the resistance decreases with the increase in temperature (or have I got the sum wrong?)

Parents
  • My local independent electrical wholesaler has various bits of kit they “hire out”  including big crimpers and cable drum handling equipment.

    If I were looking at doing this job I would be having a look in their warehouse to see what is available if needed.

    As one of my customers put it, “What you really need is one of those twenty year old Polish lads like the ground workers and solar guy have”.

    You could always order three 100 metre rolls and some trailing plugs and sockets to reduce the weight of the cable being handled at any one time, but that alters the cable selection criteria.

Reply
  • My local independent electrical wholesaler has various bits of kit they “hire out”  including big crimpers and cable drum handling equipment.

    If I were looking at doing this job I would be having a look in their warehouse to see what is available if needed.

    As one of my customers put it, “What you really need is one of those twenty year old Polish lads like the ground workers and solar guy have”.

    You could always order three 100 metre rolls and some trailing plugs and sockets to reduce the weight of the cable being handled at any one time, but that alters the cable selection criteria.

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