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Power factor (again)

Johno12345

Sorry for yet another question on this topic.

 

I have got sub metering installed on all outgoing submains, I also have a meter on the incoming main

 

Between the main meter and sub meters, I have my power factor correction

 

over a week, I'm getting about 1,500kWh of difference, the sub meters total being higher by that amount compared to the incomer meter.

 

I'd like to say that the power factor correction has effectively saved that number of kWh, is that correct?

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    Good, that is quite low. Now your savings are the difference between the now zero reactive power measured by the supply meter and your measured reactive power, correcting the phase angle uses no “extra power”, it just changes kVA into kW in a more or less lossless way. The PF correction is simply moving the current phase to match the voltage phase, rather than asking the supply to provide current when the voltage is not at its matching value. Reactive power (that is power demanded when the voltage doesn't match) looks to the source generator as extra torque, so costs in terms of excess driving power and therefore fuel.

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    Good, that is quite low. Now your savings are the difference between the now zero reactive power measured by the supply meter and your measured reactive power, correcting the phase angle uses no “extra power”, it just changes kVA into kW in a more or less lossless way. The PF correction is simply moving the current phase to match the voltage phase, rather than asking the supply to provide current when the voltage is not at its matching value. Reactive power (that is power demanded when the voltage doesn't match) looks to the source generator as extra torque, so costs in terms of excess driving power and therefore fuel.

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