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EMC bonding

lyledunn

Page 114 of GN1 states that as a rule of thumb, the mesh size required for a certain interference frequency can be determined from ensuring the diagonal of the square mesh should be no more than one-tenth of the wavelength. The example given is a 2m square mesh would therefore attenuate a 10 MHz signal. Could someone explain?

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    Speed of light = 3 x 10^8 m s¯¹ = frequency x wavelength. So if the frequency = 10^7 Hz, the wavelength = 30 m. One-tenth of that is 3 m. If the diagonal is 3 m, the sides of the square are 3/√2 ≈ 2 m.

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    Speed of light = 3 x 10^8 m s¯¹ = frequency x wavelength. So if the frequency = 10^7 Hz, the wavelength = 30 m. One-tenth of that is 3 m. If the diagonal is 3 m, the sides of the square are 3/√2 ≈ 2 m.

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