Increasing csa through warm section of an installation

Consumer unit & gas ch combi to be installed in a brick cupboard (1200 x 1200 x 2500, with concrete ceiling ) just off the kitchen. The only cable route out is up over the door and through the brick wall to the main house. I've decided on perforated tray 225mm wide for good spacing which will be mounted 10mm from the wall. I'm comfortable with the cable selection for the 6 circuits on the tray and believe I can negate the grouping factor as per note 2 for table 4C1.

For example;  the kitchen ring final ; design current of 30a, will require 6mm T&E through the hot area ( I've called the ambient temp 45 degrees) but crucially I'd like to reduce this to 4mm once I'm in the room itself and terminating to the sockets Similarly I'd intend to install the lighting cicuits through the utility cupboard and 2 metres beyond to a common junction box at standard ambient where I would reduce to 1.5mm for distribution & terminations. Is this a viable startegy and/ or am I missing a regulations prohibition?

Thanks for any comments,

Pete Murphy

Parents
  • Not sure how you arrived at 6mm2 for the RFC? I take it that you are trying to comply with overload protection requirements of 433.1.1?

    Referring to the regulation below and to column 8 of Table 4D5 (there are no figures for cable tray (Ref method E)), a 2.5mm2 has a ccc of 27A. The ambient temperature correction factor for 45C from Table 4B1 is 0.79. Therefore,  Iz = 27*0.79 = 21.33A, thereby satisfying the requirement below and allowing use of 2.5mm2. 

    You could even improve on that by reference to column 8 of Table 4D2A, which computes for Ref method E at 30A for a 2.5mm2. Either way, 2.5 is fine.

Reply
  • Not sure how you arrived at 6mm2 for the RFC? I take it that you are trying to comply with overload protection requirements of 433.1.1?

    Referring to the regulation below and to column 8 of Table 4D5 (there are no figures for cable tray (Ref method E)), a 2.5mm2 has a ccc of 27A. The ambient temperature correction factor for 45C from Table 4B1 is 0.79. Therefore,  Iz = 27*0.79 = 21.33A, thereby satisfying the requirement below and allowing use of 2.5mm2. 

    You could even improve on that by reference to column 8 of Table 4D2A, which computes for Ref method E at 30A for a 2.5mm2. Either way, 2.5 is fine.

Children
  • Afternoon Lyle,

    I got the 6mm dividing the In of 32a by Cg (0.73 , column 6 4C1) x Ca( 0.87 column 2 4B1)  to give an It of 50.38a, ( ref E table 4D2A ) although I see now both rating factors were incorrect but that's what started me on this path.

    Thanks for your time & help,

    Pete