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DC Motors - Cable sizing

Working on a project where we are replacing an existing cable serving a DC motor. The motor is 690V and has a current of 1440A. The client has advised that the existing cable is 2 x 2c 300mm2 armoured buried below ground for 130m. Now when looking at the tables in BS7671 the maximum load that a 300mm2 can take is 446A (90C) or 379A (70C) so with the parallel cables this would only provide a current-carrying capacity of 892A ( 758A @70c). We are now concerned that the existing cables installed cira 20 years ago are undersized for the full load current of the motor.


A suggestion was made that we could possibly install single-core armoured cables which would increase the current-carrying capacity. When looking at the tables in BS 7671 (Table 4E3A & Table 4D3A) there are is no data provided for when these cables are in reference method D. I have spoken to a cable manufacturer who pointed me to ERA table 6 but these current-carrying capacities would not be in line with BS7671 as they use different data. I am tempted to use the ERA data as there is no equivalent information in BS7671, Why is this not provided and would there be issues with this.


The client has limited data for the existing installation but they have not had any issues with the current cabling even though it appears undersized. Any help would be appreciated.


regards
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  • As has already been said the current cable might be sufficient IF the motor is only lightly loaded and drawing a lot less than the nameplate  rating.

    Or if the motor sees only limited use with the cable not being loaded for long enough to reach the steady state temperature suggested by the nameplate.

    Or might the existing cable be larger than believed ? Perhaps someone had last minute doubts about 300mm and installed 400mm, which would still be overloaded but not as badly. Older cables do not always have the conductor size marked on the outer sheath.


    Unless you can be reasonably certain that the motor is significantly under loaded, or that use is only short term, and WILL REMAIN SO, then in my view any replacement cables should be fully loaded in accordance with published figures.


    Remember that the existing cables MIGHT be about to fail. A common failure mode is softening of the insulation which then creeps away from the conductors, usually at bends. Not apparent from external inspection.


    Consider also the energy lost in the cables and the cost thereof. Reducing the losses from say 6% to 4% would save about 20Kw or about £3 an hour. for a long hour load that would be in the region of £25,000 a year. A quarter of a million pounds wasted in ten years puts into perspective the cost of larger cables.


    Presumably the 690 volt DC supply is obtained on site from a transformer and rectifier unit. Reducing cable losses will also reduce the load to be supplied by the transformer/rectifier and the losses therein.

    Such losses might be about 3% of full load. So reducing the load by say 20Kw will reduce the losses in the transformer/rectifier by 3% of 20Kw. About 600 watts saved, or about 10 pence an hour, or about £800 a year for long hour operation.
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  • As has already been said the current cable might be sufficient IF the motor is only lightly loaded and drawing a lot less than the nameplate  rating.

    Or if the motor sees only limited use with the cable not being loaded for long enough to reach the steady state temperature suggested by the nameplate.

    Or might the existing cable be larger than believed ? Perhaps someone had last minute doubts about 300mm and installed 400mm, which would still be overloaded but not as badly. Older cables do not always have the conductor size marked on the outer sheath.


    Unless you can be reasonably certain that the motor is significantly under loaded, or that use is only short term, and WILL REMAIN SO, then in my view any replacement cables should be fully loaded in accordance with published figures.


    Remember that the existing cables MIGHT be about to fail. A common failure mode is softening of the insulation which then creeps away from the conductors, usually at bends. Not apparent from external inspection.


    Consider also the energy lost in the cables and the cost thereof. Reducing the losses from say 6% to 4% would save about 20Kw or about £3 an hour. for a long hour load that would be in the region of £25,000 a year. A quarter of a million pounds wasted in ten years puts into perspective the cost of larger cables.


    Presumably the 690 volt DC supply is obtained on site from a transformer and rectifier unit. Reducing cable losses will also reduce the load to be supplied by the transformer/rectifier and the losses therein.

    Such losses might be about 3% of full load. So reducing the load by say 20Kw will reduce the losses in the transformer/rectifier by 3% of 20Kw. About 600 watts saved, or about 10 pence an hour, or about £800 a year for long hour operation.
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