Yes Mike, but you also need to remember the "F" in the equation above. When the inverter output is a sine wave made of many short rectangular pulses, the F is several kHz, not 50 Hz so the capacitor reactance is much smaller = much higher current! Again it's the mA which is dangerous, not the volts!
Yes Mike, but you also need to remember the "F" in the equation above. When the inverter output is a sine wave made of many short rectangular pulses, the F is several kHz, not 50 Hz so the capacitor reactance is much smaller = much higher current! Again it's the mA which is dangerous, not the volts!
