This discussion is locked.
You cannot post a reply to this discussion. If you have a question start a new discussion

Reduction of cross-sectional area between main isolator and auxiliary breaker

Hello,

I have a question regarding a specific topic.

I need to create an isolation box with 2 specific goals:

1 - To ensure a specific load is off and locked

2 - To have a secondary supply for a secondary load ensuring it is always on

With that in mind, I have considered the solution as per example attached.

My question is related to the connection between the main isolator of the Distribution Board (-QB2) and the Auxiliary breaker (-FC3).

The protection to the Distribution Board is ensured by the breaker upstream at the External Switchboard (-QA3) which ensures both cables W1, W2 and the 3 phase load are protected.

The connections to the smaller breaker have a much reduced CSA than the main supply cable W1 (2,5 vs 50 mm2).

The breaker upstream will not protect the smaller CSA cable but that is the case on many situations when busbars are not used. The auxiliary breaker (-FC3) will protect the downstream cable W3 and the load because the rating is suitable from that point downwards. But not upstream this breaker. You can say it is unprotected.

I think this is still allowed in BS7671 on a specific article 434.2 Position of devices for protection against fault current (434.2.1) where some conditions need to be met including a limitation of length.

That is my question.

Am I interpreting this correctly?

The 3 phase load is a standard load not covered under the article 433.3.3.

Any feedback will be much appreciated.

Thank you

Kind regards

Parents
  • This is a case of the difference between overload and fault protection. It is as Mike says above, but it is easy to provide fault protection as well, because you simply apply the usual adiabatic equation and a maximum conductor temperature of less than the melting point. Damage may occur but the 125A breaker will trip. You may like to check this, but as Mike says, failure is not a significant worry.

Reply
  • This is a case of the difference between overload and fault protection. It is as Mike says above, but it is easy to provide fault protection as well, because you simply apply the usual adiabatic equation and a maximum conductor temperature of less than the melting point. Damage may occur but the 125A breaker will trip. You may like to check this, but as Mike says, failure is not a significant worry.

Children
No Data