In a ring final circuit
(Based on Paul Cooks commentary of the 17th edition)
Very simple curent split using both legs of the ring
Not sure about adding up the currents in each leg
Take leg 2 Than will have the Ia of sockets 4,3 and 2
and the Ib of socket 1
How do these add up so you know the current in this leg?
Hope that makes sense
Thanks

