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Physics going on in a transformer

Former Community Member
Former Community Member

I’m trying to get a better understanding of the physics going on in a UK site transformer, those that reduce the UK mains voltage to 110V.



I’m fully aware of the basic operating principles of a transformer and the basic Power in equals V*I . Power out is the same as power in and induced voltage is given by Faradays law dependent upon the number of turns, and changing magnetic flux with time. With these we can work back from a load to determine the current draw from the secondary side of a transformer.



What I would like clarified is, depending upon the varying load on the secondary side, what at different loads is happening to the magnetic field strength in the core and the power in the primary side.



For example when I have a 1800W tool connected to my 3.3Kva 110V transformer and the power is on in the primary side but the load tool is not switched on. Obviously there is current flowing in the primary coil since there are no switches on these transformers apart from the socket switch. This will create a magnetic field which will induce an emf on the secondary windings.



If there is no load on the secondary side, is the magnetic field strength in the core and the power in the primary at its maximum even with no load on the secondary?



Or is primary input current much lower in comparison to what it could be if the transformer secondary is loaded to its maximum current output? Does putting a load on the secondary cause a feedback through the magnetic field resulting in the current increasing in the primary, hence increasing the magnetic field?



Thanks


  • Good on you - I wish that some folk writing text books bothered to check this sort of thing.

    The core sees a magnetic field that is the sum of that caused by current in primary and secondary -  and as the amp turns on both sides are equal and opposite, to a (good) first approximation  the magnetic field in the core is unaffected by changes in the load currents.

    The primary current is set by the secondary load (scaled by turns ratio), plus the 'magnetising current' which flows even when there is no load. That is set by the inductance of the primary (with no load on secondary) and the primary voltage, and is based on so many volts per turn and the volume of material in the core to be magnetised.

    M.
  • Does putting a load on the secondary cause a feedback through the magnetic field resulting in the current increasing in the primary

    I think that's got to be the case with transformers - otherwise the national grid would not have to vary generation to suit changes in LV consumption.

    https://www.gridwatch.templar.co.uk/


      - Andy.
  • Former Community Member
    0 Former Community Member
    Hello,

    I tried to attach a pdf but too big, apparently. Herewith a link to my cloud storage, though I think you need a google account.

    See part 3, monograph 2. 
    https://drive.google.com/folderview?id=1TbomXeoBbIe-IVADaOOmyyLH9le-3wAt

    Chris

    Let me know if you have a problem downloading.
  • There are two other effects too, which I will add to Mikes's description. First the unloaded transformer inductance produces a back EMF as the mains cycle varies in voltage, which opposes the input voltage so the current is small. I=L dv/dt is the equation. There are some resistive and magnetic losses so there is a small current flow, in phase with dv/dt, that is at about 90 degrees to the voltage changing. Load on the secondary decreases the effective inductance (a shorted turn type effect) so the current in the primary increases in direct relation to the load Power (kVA). The losses increase with load, both resistive and magnetic, but these are small compared to the load. Typical large transformer efficiencies are in the high 90%, depending on the size, the quality of the magnetic material, and the disposition of windings on the core.
  • 110V site transformers remember at which point of the ac wave they were switched off. Which is why they trip circuits breakers occasionally. If its switched off at a peak part of the cycle that's where it picks up from when switched back on the result is a massive surge. So I'm told..
  • It's not memory Jon, it's the switch on at peak'ish voltage is not current limited by the existing magnetic field so the back EMF, which sets the current is given by V= -L dI/dt. So to give say -350-ish volts back EMF in a very short period gives a large I, which trips the circuit. The combination of the R and L of the primary coil gives something called a time constant, which is the next bit of theory, but you should consult Hughes or a similar textbook.
  • I'll blow the dust off my Newns. Thanks Dave
  • The switch-on transient is all about the time in the cycle the volts come on, and the magentization state - or rather the lack of it, which is not a good match to the state it should be at that point in the cycle.

    It is made vastly worse if you switch near a voltage zero crossing, which would be ideal for adding a flat capacitive load, it is about the worst you can do for adding a non-magnetised  inductor. Also the majority of transformers are sized in terms of turns per volt  and core size, such that the core is within a factor of two of saturation in normal use. If you switch on at the wrong point, the peak tries to be double, but the core saturates, and in effect, once all the little magnetic domains that swing around to give the magnetic response have been jammed at one end, it is as if the core then vanishes, and the windings may as well be air-cored . The result is a spectacular current peak, and several cycles of the transformer going thud-ring to recover.

    The correct solution is to pre-magnetise the core via a moderate resistance, and then to short out the resistor after a few cycles,  or to apply power via a thermistor, whose resistance drops to near zero as it self heats.

    Modern electronic soft starts, can put the mains on just after the top dead centre of the voltage waveform, which is the point when the core would normally not be very magnetised, so it starts on the falling voltage.


    Further to the above, and concerns about how transformers relay the load from one side to the other, to be rigorous, I will clarify that  the B field in the core is only almost constant, and to first order is only a function of applied voltage,frequency, and core geometry.

    Drawing current from the secondary causes the current in the primary to rise to keep the field constant, and the change in amp turns is equal and opposite on primary an secondary  sides, (well almost, losses ignored here and good magnetic coupling assumer), so the B field in the core remains (almost) constant.

    Looking in at the primary side, the impedance presented is the effective inductance of the primary, then shunted by the transformed version of the secondary load.

    B field in core does vary with load for non constant voltage transformers, such as current transformers .

    some text book explanations are not always clear on this.

    Mike
  • Former Community Member
    0 Former Community Member

    So I read your responses which left me thinking further about the original question.


    Would I be correct in stating the following and if so please feel free to expand in greater detail, or correct, though having read Mikes last post I think you may have already beaten me to the punch.



    With no load on the secondary there is a 'magnetising current in the primary the size of which depends upon the design and build quality of the transformer. This primary current creates the magnetic field around the core, alternating back and forth. 


    The strength of the magnetic field is given by the equation, B = u*n*l (permeability * number of turns * current) 


    The energy in the magnetic field is 


    2af12182fd7c13795f11fb157f016624-original-image.png

    Therefore the amount of energy in the magnetic field is dependent upon the size of the primary current. Power is the rate of energy conversion which for the primary will be electric to magnetic energy at voltage * current. There will be a loss of energy due to Lenz's law across the primary coil.


    The magnetic field induces an emf on the secondary coil. This when loaded will draw a current. This current too will as a result of Lenz's law result in a further partial loss of energy from the magnetic field.


    This induced magnetic field as a result of the current on the secondary actually counteracts the total size of the magnetic field from the primary, and therefore the energy in it.


    If you could take an instant snap shot in time and at the same time not cause a change in the primary current this reduction in the size of the magnetic field from the primary means the amount of energy in the magnetic field available has to decrease too. The rate of this reduction has to be matched by the rate of energy withdrawal from the magnetic field at the secondary side which explains why with voltage fixed the current has to increase in a step down transformer. 


    In reality until the transformer is fully loaded to its maximum Kva rating the current in the primary will increase putting energy back into the magnetic field to maintain the energy levels which with its maximum available size per given current has to have a matching energy withdrawal at the secondary side. 


    ​​​​​​​Neil


  • I think the suggestion made by Mike that the magnetic field strength is constant is slightly misleading, I am sure not deliberately but it leads from another phenomenen which is usually not mentioned in textbooks. I will attempt to explain it. Imagine you have a toroidial core, with a winding spaced from another on the opposite side of the toroid. Imagine the energy flow between the windings, the magnetic field in the core carries this energy from one side to the other. Loading MUST increase this magnetic field energy transfer, and it does, and causes increased losses. But this may be imagined in the second winding reducing the magnetic field in the same way as the primary winding increases it. However magnetic circuits do not work quite like that, and that is why practical transformers have the secondary winding wound on top of the primary winding, but still with a complete magnetic circuit (the core in a loop). Magnetism in this toroidial confguration has "resistance" and loss, but if the same piece of magnetic material has both the primary gain and secondary loss in the same place it is very efficient. One still needs the core to work, but the whole arrangement and "magnetic circuit" is not quite as often described. There are many things about magnetism (and electricity) which we do not fully understand, whatever you read in "text books", these are usually just restatements of that which is written elsewhere. The important thing is to keep an open mind and think about the problem, it may well not be quite as others describe. but consider things like energy flow above. The idea that a coupled winding reduces the magnetid field is somewhat counter intuitive, but if you think about it inductors of all kinds have slightly strange energy flows, think about "back EMF" in energy terms and it is obvious that the magnetic field energy must go somewhere when the magnetising current stops!


    David CEng etc.